Our next two benchmarks, 7 and 8, are on writing equations of parallel and perpendicular lines. Here are the notes that we took in class. It’s pretty much the same as benchmark 6, except the slope for parallel lines are the same and opposite reciprocals for perpendicular lines.
We had 2 assignments, #14 Parallel and Perpendicular Worksheet and #15 1.6 and 1.7C WS. #14 was due by the end of class (unless you were absent!).
Coming Up: Benchmark 6 on Monday
Posting for Points Question:
Make up a slope for a line. Then find the slope of the line parallel and the slope of the line perpendicular.
9 Comments
October 3, 2007 at 5:51 pm
PARALLEL LINES TWO LINES THAT ARE COPLANAR AND DO NOT INTERSECT THE SYMBOL FOR THIS IS 11.
LINE #1 : M=3
LINE #2 : THROUGH (9,0)
PARALLEL M=3
0=3(9)+B
0=27 +B
B= -27
Y=3X-27
PERPENDICULAR M=3-1
3
O=-1 (9) +
3
O=-3 +B
3=B
October 3, 2007 at 10:09 pm
PARALLEL PERPENDICULAR
y=1x+1 but through (2,2) y=4x+2 but through (0,3)
m=1 m=1/6 (flip) =6
(2)=1(1)+b 3=6(0)+b
2=1+b 3=0+b
3=b 3=b
y=1x+3 y=6x+3
October 3, 2007 at 10:18 pm
OOPS!!!!!
parallel
y=1x+1 -(2,2)
m=1
2=1(1)=b
2=1=b
3=b
y=1x+3
perpendicular
y=4x+2 – (0,3)
m=6 with flip
3=6(0)+b
3=0+b
3=b
y=6x+3
October 4, 2007 at 5:25 pm
Line 1: m=4
Line 2: Through (10,2)
Parallel Equation
2=4(10)+b
2=40+b
b=20
y=4x+20
_______________________________________________
Perpendicular Equation
2=-4(10)+b
2=160+b
b=80
y=-4x+80
October 6, 2007 at 11:20 am
line 1: m = 1/6
line 2: through (4,3)
Parallel
3=6(4)+b
3= 24+b
-24 -24
-21=b
y=6x-21
***********************************************************
Perpendicular
y=-1/6x+b
3=-1/6(4)+b
3=-4/6+b
6(3)=(-4/6+b)6
18=-4+b
+4 +4
22=b
y=-1/6x+22
October 7, 2007 at 9:07 am
Line1:m= -10
Line2: (6,5)
Parallel line m= -10
y= mx+b
5= -10(6)+b
5= -60+b
65=b
y= -10+65
_________________________________________________
Perpendicular line m=10/1
y=mx+b
5=10/1(6)+b
5=60/1+b
5=60+b
-55=b
y= 10/1-55
October 8, 2007 at 4:46 pm
4,8 6,12
-4
_
-2
y=mx+b
4=2(8)+b
4=16+b
-16 -16
-12=b
?
nicosha
October 8, 2007 at 4:54 pm
4,8 6,12
-4
_
-2
y=mx+b
8=2(4)+b
8=8+b
-8 -8
0=b
sorry i mixed up the points
October 8, 2007 at 6:33 pm
m=1\2
(-2,1)
parallel to y=1\2x-4
(1)=1\2(-2)-b
1\2*-2\2=-1
1=-b
2=b
y=1\2x+2
perpendicular
(-2,1)toy=1\2x-4
(1)=-2\1(-2)+b
(1)=-1(-2)+b
1=4+b
-4
-3=b
y=-2x-3
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